141 lines
2.9 KiB
Python
141 lines
2.9 KiB
Python
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# coding=utf-8
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"""
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Class for handling the odd permutations of an 'issue number' that the comics industry throws at us
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e.g.:
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"12"
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"12.1"
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"0"
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"-1"
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"5AU"
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"100-2"
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"""
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"""
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Copyright 2012-2014 Anthony Beville
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Licensed under the Apache License, Version 2.0 (the "License");
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you may not use this file except in compliance with the License.
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You may obtain a copy of the License at
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http://www.apache.org/licenses/LICENSE-2.0
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Unless required by applicable law or agreed to in writing, software
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distributed under the License is distributed on an "AS IS" BASIS,
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WITHOUT WARRANTIES OR CONDITIONS OF ANY KIND, either express or implied.
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See the License for the specific language governing permissions and
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limitations under the License.
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"""
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import utils
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import math
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import re
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class IssueString:
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def __init__(self, text):
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# break up the issue number string into 2 parts: the numeric and suffix string.
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# ( assumes that the numeric portion is always first )
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self.num = None
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self.suffix = ""
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if text is None:
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return
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if type(text) == int:
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text = str(text)
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if len(text) == 0:
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return
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text = unicode(text)
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#skip the minus sign if it's first
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if text[0] == '-':
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start = 1
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else:
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start = 0
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# if it's still not numeric at start skip it
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if text[start].isdigit() or text[start] == ".":
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# walk through the string, look for split point (the first non-numeric)
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decimal_count = 0
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for idx in range( start, len(text) ):
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if text[idx] not in "0123456789.":
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break
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# special case: also split on second "."
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if text[idx] == ".":
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decimal_count += 1
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if decimal_count > 1:
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break
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else:
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idx = len(text)
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# move trailing numeric decimal to suffix
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# (only if there is other junk after )
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if text[idx-1] == "." and len(text) != idx:
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idx = idx -1
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# if there is no numeric after the minus, make the minus part of the suffix
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if idx == 1 and start == 1:
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idx = 0
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part1 = text[0:idx]
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part2 = text[idx:len(text)]
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if part1 != "":
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self.num = float( part1 )
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self.suffix = part2
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else:
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self.suffix = text
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#print "num: {0} suf: {1}".format(self.num, self.suffix)
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def asString( self, pad = 0 ):
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#return the float, left side zero-padded, with suffix attached
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if self.num is None:
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return self.suffix
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negative = self.num < 0
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num_f = abs(self.num)
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num_int = int( num_f )
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num_s = str( num_int )
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if float( num_int ) != num_f:
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num_s = str( num_f )
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num_s += self.suffix
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# create padding
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padding = ""
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l = len( str(num_int))
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if l < pad :
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padding = "0" * (pad - l)
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num_s = padding + num_s
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if negative:
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num_s = "-" + num_s
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return num_s
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def asFloat( self ):
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#return the float, with no suffix
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if self.suffix == u"½":
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if self.num is not None:
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return self.num + .5
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else:
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return .5
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return self.num
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def asInt( self ):
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#return the int version of the float
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if self.num is None:
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return None
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return int( self.num )
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